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I wonder how to solve:

[tex]I=\int_{-\infty}^{\infty}e^{-u^2}\frac{1}{1+Cu} du[/tex]

I have solved:

[tex]\int_{-\infty}^{\infty}e^{-u^2}du[/tex]

which equals

[tex]\sqrt{\pi}[/tex]

and I solved it with polar coordinates and variable substitution.

Thankful for help!

Best regards, Edison

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# I Integral problems with polar coordinates and variable substitution

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