- #1
Edison Bias
- 105
- 5
H!
I wonder how to solve:
[tex]I=\int_{-\infty}^{\infty}e^{-u^2}\frac{1}{1+Cu} du[/tex]
I have solved:
[tex]\int_{-\infty}^{\infty}e^{-u^2}du[/tex]
which equals
[tex]\sqrt{\pi}[/tex]
and I solved it with polar coordinates and variable substitution.
Thankful for help!
Edison
I wonder how to solve:
[tex]I=\int_{-\infty}^{\infty}e^{-u^2}\frac{1}{1+Cu} du[/tex]
I have solved:
[tex]\int_{-\infty}^{\infty}e^{-u^2}du[/tex]
which equals
[tex]\sqrt{\pi}[/tex]
and I solved it with polar coordinates and variable substitution.
Thankful for help!
Edison