B Integral test and its conclusion

AI Thread Summary
The Integral Test is used to determine the convergence or divergence of an infinite series by comparing it to an improper integral. When the integral of a function f(x) diverges, as shown in the example with ∫0^∞ 3x dx resulting in infinity, the corresponding series also diverges. In this case, the series 0 + 3 + 6 + 9 + 12 + ... diverges because its related integral diverges. The discussion emphasizes the importance of visualizing the function and the areas of rectangles representing the series' terms to understand the relationship between the two. Overall, the Integral Test provides a method to assess series behavior based on the behavior of integrals.
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I'm really confused about this test. Suppose we let f(n)=an and f(x) follows all the conditions.
When you take the integral of f(x) and gives you some value. What are you supposed to conclude from this value?
 
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The Subject said:
When you take the integral of f(x) and gives you some value. What are you supposed to conclude from this value?

Look at an example. What value do you get from \int_0^\infty 3x\ dx ?
 
ok so I get
$$\lim_{t \to \infty} \int_0^t 3x dx = \lim_{t \to \infty} \frac{3}{2}x^2 |_0^t=lim_{t \to \infty} \bigg(\frac{3}{2}t^2 - \frac{3}{2}0^2\bigg)=\infty$$
 
The Subject said:
$$=\infty$$

So what does the integral test say about the convergence or divergence of the infinite series ##0 + 3 + 6 + 9 + 12 + ...## ?
 
The series 0 + 3 + ... diverges. Since f(x) div, an also diverges. I get it how to use it now.

Thanks!
 
The Subject said:
Although I don't intuitively understand why this is true. .

Sketch a function with a positive graph and, on top of that, sketch the rectangles whose areas represent the terms of the related series. These rectangles have bases [0,1], [1,2] ... etc. and heights determined by the function's value at the left endpoints. The area of the rectangles is not a particularly good approximation to the area under the graph, but the intuitive idea is that the two areas are either both finite or both infinite.
 
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