- #1
Cummings
- 53
- 0
need to integrate 1/(1+e^x)
by using th rule 1/(ax+b) = (1/a)ln(ax+b)+c
i got (1/e^x)ln(1+e^x)+c
that is correct is it not?
because if i now differentiate that, i get 1/(1+e^x)..which is what we start with.
I am damn sure this is right, but its causing some arguments.
by using th rule 1/(ax+b) = (1/a)ln(ax+b)+c
i got (1/e^x)ln(1+e^x)+c
that is correct is it not?
because if i now differentiate that, i get 1/(1+e^x)..which is what we start with.
I am damn sure this is right, but its causing some arguments.
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