- #1

Roodles01

- 128

- 0

∫ f(x)g'(x) dx = f(x)g(x) - ∫f'(x)g(x) dx

I have what is an innocuous looking part of an equation which I can't solve.

the f(x) part in this case is;

ln(5x) which is easy enough i.e. 1/x

the second part 1/(x

^{(2/3)}) is the bit I can't solve.

The standard I have for

1/x is ln(x)+c

& the standard I have for x

^{n}is (1/(n+1))x

^{n+1}+c

But these don't solve this for me

I have checked on WolframAlpha & NumberEmpire & they give the same answer

3 cuberoot 3

I have tried just this bit by itself & go t nowhere. Could someone help with how I should get 3 cuberoot 3, please.