Integrating 8/(xln(3x))dx | Solving for ln(3x) | Homework Help

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SUMMARY

The integral of the function (8)/(xln(3x))dx can be solved by using the substitution method. By letting u = ln(3x), the differential du becomes 1/x dx, allowing the integral to be rewritten as 8/udu. Upon integrating, the result is 8ln(u), which translates to 8ln(ln(3x)). The final answer includes the constant of integration and absolute value bars, yielding 8ln |ln(3x)| + C.

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Homework Statement



Integrate: (8)/(xln(3x))dx


Homework Equations





The Attempt at a Solution



I separated the equations into 8/x and 1/(ln3x). I sub u for ln(3x) and I got 1/x for du. Since I had 8/x, I made it 8du. So the new integration will be 8/udu. I integrated so it will be 8lnu and then it will become 8ln(ln3x). What's next?
 
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mshiddensecret said:

Homework Statement



Integrate: (8)/(xln(3x))dx

Homework Equations


The Attempt at a Solution



I separated the equations into 8/x and 1/(ln3x). I sub u for ln(3x) and I got 1/x for du. Since I had 8/x, I made it 8du. So the new integration will be 8/udu. I integrated so it will be 8lnu and then it will become 8ln(ln3x). What's next?


Not much. Just add the constant of integration. And you might want absolute value bars:$$
8\ln |\ln(3x)|+C$$
 

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