- #1
snowJT
- 117
- 0
I Just want to know if this is how this should be done..
[tex]\frac{dy}{dx} = \frac{3y^2}{x}[/tex]
[tex]dy = \frac{3y^2}{x}dx[/tex]
[tex]dy = 3^2 x^-^1dx[/tex]
[tex]\frac {1}{3} \int \frac {dy}{y^2} = \int x^-^1dx[/tex]
[tex]\frac {1}{3} ln| y^2| = ln | x | + C[/tex]
because I forget how to integrate the polynomial...
[tex]\frac{dy}{dx} = \frac{3y^2}{x}[/tex]
[tex]dy = \frac{3y^2}{x}dx[/tex]
[tex]dy = 3^2 x^-^1dx[/tex]
[tex]\frac {1}{3} \int \frac {dy}{y^2} = \int x^-^1dx[/tex]
[tex]\frac {1}{3} ln| y^2| = ln | x | + C[/tex]
because I forget how to integrate the polynomial...