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I need to find an integrating factor of the form x^n*y^m, to solve a differential equation i have... however i do not know the process to solve for an integration of this form.. .any help??

Thanks

Steph

- Thread starter bemigh
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- #1

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I need to find an integrating factor of the form x^n*y^m, to solve a differential equation i have... however i do not know the process to solve for an integration of this form.. .any help??

Thanks

Steph

- #2

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can you give an example problem that your working on?

- #3

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and it says, find an integrating factor of the form (x^n) * (y^m), and solve the equation...

thanks sweetie

steph

- #4

HallsofIvy

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Homework Helper

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RULE 1: Mathematics problems are not solved by staring at a problem until you remember the answer! They are solved by plugging things in and doing the algebra.

So TRY!!

If you multiply the equation by [itex]x^ny^m[/itex] you get

[itex](12x^ny^m+ 5x^{n+1}y^{m+1})dx+ (6x^{n+1}y^{m-1}+ 3x^{n+2}y^m)dy= 0[/itex]

In order for that to be an exact equation, you must have

[itex](12x^ny^m+ 5x^{n+1}y^{m+1})_y= (6x^{n+1}y^{m-1}+ 3x^{n+2}y^m)_x[/itex]

Do the derivatives and see what m and n must be for those to be equal!

[itex](12x^ny^m+ 5x^{n+1}y^{m+1})_y= 12mx^ny^{m-1}+ 5(m+1)x^{n+1}y^m[/itex]

[itex](6x^{n+1}y^{m-1}+ 3x^{n+2}y^m)_x= 6(n+1)x^ny^{m-1}+3(n+2)x^{n+1}y^m[/itex]

Coefficients of the same powers must be equal. That gives two equations for m and n.

So TRY!!

If you multiply the equation by [itex]x^ny^m[/itex] you get

[itex](12x^ny^m+ 5x^{n+1}y^{m+1})dx+ (6x^{n+1}y^{m-1}+ 3x^{n+2}y^m)dy= 0[/itex]

In order for that to be an exact equation, you must have

[itex](12x^ny^m+ 5x^{n+1}y^{m+1})_y= (6x^{n+1}y^{m-1}+ 3x^{n+2}y^m)_x[/itex]

Do the derivatives and see what m and n must be for those to be equal!

[itex](12x^ny^m+ 5x^{n+1}y^{m+1})_y= 12mx^ny^{m-1}+ 5(m+1)x^{n+1}y^m[/itex]

[itex](6x^{n+1}y^{m-1}+ 3x^{n+2}y^m)_x= 6(n+1)x^ny^{m-1}+3(n+2)x^{n+1}y^m[/itex]

Coefficients of the same powers must be equal. That gives two equations for m and n.

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