- #1

bayan

- 203

- 0

I am trying to find what is the volume of the [tex]y=\frac{a}{x^2}+b[/tex] is when it is rotated in y-axis.

The values of a is 1 and b is -1.

max hight is 3 and min is 0.

I was trying to integrade and ended up with [tex]V=\frac{-Pi}{y^2+2Y+1}[/tex] where y is 3.

Is this right?

I did a U substitution to integrade [tex]x^2=\frac{1}{y+1}[/tex]

Plz help.