Integrating \frac{x^3}{(x+1)^8}: Tips & Hints

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Homework Help Overview

The discussion revolves around the integration of the function \(\frac{x^3}{(x+1)^8}\). Participants are exploring methods to approach this integral, which is situated within the context of calculus, specifically Calculus 2.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants express uncertainty about how to start the integration process, with some attempting substitutions that do not seem to yield useful results. There is mention of considering partial fractions, but concerns are raised about the complexity of having multiple variables to solve for. Others suggest that a simpler method may exist.

Discussion Status

Some guidance has been offered regarding a substitution that transforms the integral into a more manageable form. Participants are actively engaging with each other's ideas, exploring different approaches without reaching a consensus on the best method yet.

Contextual Notes

Participants note that the problem is part of a larger set of integrals, and there is a sense of frustration regarding the perceived difficulty of the problem relative to their current understanding of calculus.

bob1182006
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Homework Statement


[tex]\int\frac{x^3 dx}{(x+1)^8}[/tex]

Homework Equations


None I can think of.

The Attempt at a Solution


Hm..I just don't know where to start.

No substitution seems to be useful. (u=x+1, u=(x+1)^8).
I've tried pulling x out of the denominator to get:
[tex]\int\frac{x^3 dx}{x^8 (1+x^-1)^8}[/tex]
but that doesn't help either..

This isn't really HW just one of 15 integrals I was given that I should be able to do...

Thanks in Advance for any hints on solving this.
 
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bob1182006 said:

Homework Statement


[tex]\int\frac{x^3 dx}{(x+1)^8}[/tex]


Homework Equations


None I can think of.


The Attempt at a Solution


Hm..I just don't know where to start.

No substitution seems to be useful. (u=x+1, u=(x+1)^8).
I've tried pulling x out of the denominator to get:
[tex]\int\frac{x^3 dx}{x^8 (1+x^-1)^8}[/tex]
but that doesn't help either..

This isn't really HW just one of 15 integrals I was given that I should be able to do...

Thanks in Advance for any hints on solving this.
Cal 2? b/c i can't even go at it, I've only completed Cal 1.
 
Yep, Calc 2.

I "think" I could do partial fractions but...8 variables to find? and then 8 integrals of increasing power on the denominator. I think there should be an easier way...
 
bob1182006 said:
Yep, Calc 2.

I "think" I could do partial fractions but...8 variables to find? and then 8 integrals of increasing power on the denominator. I think there should be an easier way...
man i can't wait to be able to solve these types of problems :-]

i've missed it so much that i even did the even problems that weren't assigned for hw
 
u=x+1 is fine. Turns it into (u-1)^3/u^8. Now you just have to expand (u-1)^3. And if that's the worst of your 15 problems, feel blessed. It's really a calc 1 problem.
 
Last edited:
Wow thanks, this is about the 2nd time I've ever seen that type of substitution being used >.<.

Yea the problem's weren't really hard Calc 2 stuff mainly things we should know off the top of our heads.
 

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