- #1
kingwinner
- 1,270
- 0
Q: Given that G(x,y,z)=(6xz+x3, 3x2y+y2, 4x+2yz-3z2). Find F such that curl F = G.
Solution:
...
A particular solution is
Fo=(-3x2yz-y2z, 2x2-3xz3-x3z)
And then my textbook says that the general solution is F=Fo + grad f where f is an arbitrary C1 function.
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Now my questions:
If f is C1 function, why must F=Fo+gradf be a solution to curl F=G?
I believe that curl(grad f)=0 for f a C2 (not C1) function. Why does C1 work as well?
Secondly, why can we be sure that F=Fo+gradf is the general solution to curl F=G? (i.e. why is every solution contained in it?)
I would really appreciate if someone could explain.
Solution:
...
A particular solution is
Fo=(-3x2yz-y2z, 2x2-3xz3-x3z)
And then my textbook says that the general solution is F=Fo + grad f where f is an arbitrary C1 function.
===============================
Now my questions:
If f is C1 function, why must F=Fo+gradf be a solution to curl F=G?
I believe that curl(grad f)=0 for f a C2 (not C1) function. Why does C1 work as well?
Secondly, why can we be sure that F=Fo+gradf is the general solution to curl F=G? (i.e. why is every solution contained in it?)
I would really appreciate if someone could explain.