(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

[tex]

\int {\frac{{\cos ydy}}

{{\sin ^2 y + \sin y - 6}} }

[/tex]

3. The attempt at a solution

[tex]

\int {\frac{{\cos ydy}}

{{\sin ^2 y + \sin y - 6}} = } \int {\frac{{\cos ydy}}

{{(\sin y - 2)(\sin y + 3)}}}

[/tex]

Now I attempt to split this into partial fractions:

[tex]

\begin{gathered}

\frac{{\cos y}}

{{(\sin y - 2)(\sin y + 3)}} = \frac{A}

{{\sin y - 2}} + \frac{B}

{{\sin y + 3}} \hfill \\

\cos y = A(\sin y + 3) + B(\sin y - 2) \hfill \\

\cos y = A\sin y + 3A + B\sin y - 2B \hfill \\

\cos y = (A + B)\sin y + 3A - 2B \hfill \\

\end{gathered}

[/tex]

....from here i'm not sure what to do to solve for the coefficients. I can't see any trig identities that would help either. How would you solve for these?

Thank you.

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# Homework Help: Integration By Parts - Another Problem

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