Integration by parts help just the beginning part for this one

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SUMMARY

The discussion centers on the integration of the function (sin(3t))^4 from 0 to π using integration by parts and substitution methods. The user encountered issues with the substitution method, specifically when substituting 3t with u, leading to incorrect coefficients in the final answer. The confusion arises from not properly adjusting the limits of integration and the differential when applying the substitution. The user successfully solved the integral without substitution, indicating that the substitution method was misapplied.

PREREQUISITES
  • Understanding of integration techniques, specifically integration by parts.
  • Familiarity with substitution methods in calculus.
  • Knowledge of trigonometric functions and their integrals.
  • Ability to manipulate limits of integration during substitution.
NEXT STEPS
  • Review the method of integration by parts in calculus.
  • Study the proper application of substitution in definite integrals.
  • Practice integrating trigonometric functions, particularly powers of sine and cosine.
  • Learn how to correctly change limits of integration when performing substitutions.
USEFUL FOR

Students studying calculus, particularly those learning integration techniques, and educators looking for examples of common pitfalls in substitution methods.

camboguy
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Homework Statement


intergral from pi to 0.
of
(sin(3t)dt)^4






The Attempt at a Solution



okay so i know how to do this but when i tried substitution putting 3t=u and (1/3)du= dt i always came with the the wrong coefficient at the end with the answer and so i would multiply it wrong. but then when i do not use u/du substitution everything works well? why is that? what is the difference? and I am using u/du substitution improperly or something?
 
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Are you correctly changing the limits?
 
i didn't need to change it because i just plugged back in the variables u with 3t. just wondering it should be correct even if i substitute right?
 

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