Integration by parts, how to find int 1/(x (ln 3)^2) dx

[intenzxboi]

Homework Statement

int dx / (x (ln 3)^3)

can someone tell me how to start this problem what's my u and dv ??

 

[Dick]

You've got to mean dx/(x*ln(x)^3). Just do u=ln(x). That's all.

 

[intenzxboi]

opps actually problem is int dx / (x (ln x)^3)

so u = ln x
du= 1/x dx

int 1/ u^3 dx

 

[Dick]

1/u^3 du. Not dx.

 

[intenzxboi]

right.. thanks