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Integration by parts, how to find int 1/(x (ln 3)^2) dx

  1. Feb 13, 2009 #1
    1. The problem statement, all variables and given/known data

    int dx / (x (ln 3)^3)

    can someone tell me how to start this problem whats my u and dv ??
     
  2. jcsd
  3. Feb 13, 2009 #2

    Dick

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    Re: Integration

    You've got to mean dx/(x*ln(x)^3). Just do u=ln(x). That's all.
     
  4. Feb 13, 2009 #3
    Re: Integration

    opps actually problem is int dx / (x (ln x)^3)

    so u = ln x
    du= 1/x dx

    int 1/ u^3 dx
     
  5. Feb 13, 2009 #4

    Dick

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    Re: Integration

    1/u^3 du. Not dx.
     
  6. Feb 13, 2009 #5
    Re: Integration

    right.. thanks
     
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