- #1

SYoungblood

- 64

- 1

## Homework Statement

I'm going to cut from the initial part of the problem, which I am confident is good to go, and cut straight to the antiderivatives.

## Homework Equations

All antiderivatives are to be integrated on the interval from 0 to π/18

(I

_{1}) = -1/9 cos 9x - (I

_{2}) (-2/27 * cos

^{3}(9x)) + (I

_{3}) (-1/45 * cos

^{5}(9x)

## The Attempt at a Solution

For I

_{1}-- (π)/18) -- -1/9 cos 9π/18 = -1/9 cos π/2 = 0

-1/9 cos 0 = -1/9

0 - (-1/9) = 1/9

ForI

_{2}-- ( π/18) -- -2/27 cos 9π/18 = -2/27 cos π/2 = 0

-2/27 cos 0 = -2/27

0 - (-2/27) = 2/27

For I

_{3}-- (π/18) -- -1/45 cos 9π/18 = -1/45 cos π/2 = 0

-1/45 cos 0 = -1/45

0- (-1/45) = 1/45

1/9 - 2/27 + 1/45 = 8/27, or 40/135 -- However, the answer in my text is 8/135.

Again, I am positive on my getting the antiderivatives right, I am sure the error is in the computing of the definite integrals. I thank you in advance for all help.

SY

Last edited: