- #1

- 19

- 0

## Homework Statement

[tex]

\int\arctan(4t)dt

[/tex]

## Homework Equations

## The Attempt at a Solution

[tex]

\int\arctan(4t)dt = t\arctan(4t) -4 \int \frac{t}{1+16t^2}dt

[/tex]

I'm stuck at this point. I think I need to make a substitution for the denominator, but I'm not sure how to go about doing so.