- #1

sugarxsweet

- 12

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## Homework Statement

Evaluate the following indefinite integral:

∫(sin(ln16x))/xdx

## Homework Equations

## The Attempt at a Solution

let u = ln16x

therefore du=16/16x=1/x

∫sinudu

=-cosu

=-cos(ln16x)

Why is this showing as the wrong answer?