- #1
sugarxsweet
- 12
- 0
Homework Statement
Evaluate the following indefinite integral:
∫(sin(ln16x))/xdx
Homework Equations
The Attempt at a Solution
let u = ln16x
therefore du=16/16x=1/x
∫sinudu
=-cosu
=-cos(ln16x)
Why is this showing as the wrong answer?