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Integration of inverse trig functions

  1. Feb 7, 2012 #1
    1. The problem statement, all variables and given/known data


    Screenshot2012-02-07at92737PM.png

    This is an integration of an inverse trig function.
    I don't see how they go from 1/2 to 1/4. I understand how they get the 1/2, du = 2dx, divide both sides by 2, but where does the 1/4 come from?
     
  2. jcsd
  3. Feb 7, 2012 #2
    Ok, i've done some more research and looks like if anything the 1/2 should just be canceled out because you're supposed to put du in the numerator, which is 2 and 2 times .5 = 1.
     
  4. Feb 7, 2012 #3
    never mind, it looks like 1/4 but it's really 1/2. the book cut off the top part of 1/2 to make it look like 1/4. i found some guy on youtube doing the exact same problem.
     
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