In the Tsiolkovsky rocket equation derivation there is a part that says:(adsbygoogle = window.adsbygoogle || []).push({});

[tex]\frac{dV}{dt} = -\upsilon_e \frac{1}{m} \frac{dm}{dt}[/tex]

"Assuming v_e, is constant, this may be integrated to yield:"

[tex]\Delta V\ = v_e \ln \frac {m_0} {m_1} [/tex]

How does this work? The differential is an operator and I am pretty sure you just can't cancel the dt. I wonder what assumptions are needed to be able to legally just remove the "dt"s though.

Thanks!

**Physics Forums - The Fusion of Science and Community**

# Integration of Tsiolkovsky rocket equation

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

Have something to add?

- Similar discussions for: Integration of Tsiolkovsky rocket equation

Loading...

**Physics Forums - The Fusion of Science and Community**