Integration: Rationalizing and then Partial Fractions

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SUMMARY

The integral discussed is \int\frac{e^x \cos(\log_7(e^x+9))}{(e^x+9) \ln(7)}dx. The substitution u = e^x + 9 simplifies the integral to \int\frac{\cos(\log_7(u))}{u \ln(7)}du. The user considers using the relationship \log_7(u) = \frac{\ln(u)}{\ln(7)} to further simplify the integral. The discussion emphasizes the importance of applying logarithmic identities and partial fraction decomposition to solve the integral effectively.

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  • Knowledge of substitution methods in integration
  • Experience with partial fraction decomposition
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  • Study the properties of logarithms in integration
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  • Explore partial fraction decomposition methods
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Homework Statement


\int\frac{e^xcos(log_7(e^x+9))}{(e^x+9)ln(7)}dx


Homework Equations





The Attempt at a Solution


Let u= (ex+9)
du= exdx
New integral \int\frac{cos(log_7(u))}{(u)ln(7)}du
This is where I got l little lost. Should I let log7(u)=\frac{ln(u)}{ln(7)}? Or is this just a waste of time. I was thinking after that I would use log rules to make it ln(u)-ln(7) and then split it into two separate integrals and follow that by partial fractions. I'm just curious if I'm on the right track.
 
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Just let t=\log_7 u. Then only constant times integral of cosine is left.
 

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