Integration time for poissonian signal

[RHK]

Homework Statement

Observing a star with a telescope where a photomultiplier is applied, 5 photons per second are detected on the average.
Assuming a Poissonian statistics and the the background is negligible, determine the integration time useful to measure the flux with a standard deviation of 5% of the average flux, and the determine the magnitude error.

Homework Equations

Poissonian statistic: P(n)=e^{-\lambda}{\lambda^n}/{n!}

The Attempt at a Solution

I can not outline the problem... Any suggestion please?

 

[RHK]

Maybe i found a solution.
For a poissonian distribution, the mean value and the variance are equal.
As the standard deviation is the 5% of the mean, this can be translated in:

√X = 5% X that's X = mean = 400.

So, to collect 400 photons with a mean rate of 5 photons per second, then 80 seconds are needed.

What about this? And for the second point?
Please I need suggestions :)

 

[RHK]

Is there anybody that can help me?

 

[Liquidxlax]

you might have more help in the statistical section of the forum. I've done this stuff before, but this problem seems a bit screwy to me

 

[RHK]

Maybe you're right :) thanks

 

[Redbelly98]

Maybe i found a solution.
For a poissonian distribution, the mean value and the variance are equal.
As the standard deviation is the 5% of the mean, this can be translated in:

√X = 0.05 X that's X = mean = 400.

Yes, correct.
(The "%" character does not show up in LaTeX, so I have edited this quoted version of your post: 5% --> 0.05)

So, to collect 400 photons with a mean rate of 5 photons per second, then 80 seconds are needed.

Yes, I agree.

What about this? And for the second point?
Please I need suggestions :)

What equation is there for giving the magnitude?

EDIT:

you might have more help in the statistical section of the forum. I've done this stuff before, but this problem seems a bit screwy to me

I'm inclined not to move this thread; the statistics part of the problem has been answered.

 

[RHK]

For the magnitude, can I use the relation: m = -2.5 log F ?
And then propagate the error?
I'm not sure at all...

 

[Redbelly98]

For the magnitude, can I use the relation: m = -2.5 log F ?
And then propagate the error?
I'm not sure at all...

Yes, that is exactly what to do

 

[RHK]

Ok, let's try :)

The error for the magnitue can be found by using: \Delta m = |\frac{∂m}{∂F}| \Delta F

where \Delta F = σ(F) = 0.05\times X = 0.05\times 400 = 20

and the derivative |\frac{∂m}{∂F}| = 2.5 |\frac{∂}{∂F} log F| = \frac{2.5}{ln 10} \times 1/F

So: \Delta m = \frac{1.086\times 20}{400} = 0.054

That is about the same of the flux error.
It seems reasonable.

 

[Redbelly98]

Looks good.

 

[RHK]

Thank you!