Integration with sqrt in denominator

[senorarosada]

I wonder how would I get out the integral when the denominator is square-rooted.

∫\frac{1}{\sqrt{3x-x^2}} dx

 

[dodo]

Hi,
http://www.sosmath.com/calculus/integration/trigsub/trigsub.html

Be sure to read till the end, where it speaks of "completing the square".

 

[JJacquelin]

3x-x² = (3/2)²-(x -(3/2) )²
Let (x -(3/2) )= (3/2)*sin(t)
or let (x -(3/2) )= (3/2)*sinh(t)