Integration with Trig Substitution

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Homework Help Overview

The discussion revolves around an integral related to the electric field strength of a continuous charge distribution. The original poster presents an integral involving a trigonometric substitution and expresses uncertainty about solving it.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of trigonometric substitution as a potential method for solving the integral. There are questions about the correct setup and the variables involved in the integration process. Some participants express confusion and seek further hints without revealing complete solutions.

Discussion Status

The conversation reflects a mix of attempts to clarify the integral and the methods available for solving it. While some participants suggest specific approaches, others express frustration and seek additional guidance. There is no clear consensus on the best method to proceed.

Contextual Notes

The integral is specified as a definite integral from infinity to negative infinity, and there are references to the need for a trigonometric-free final answer. Participants also mention the relevance of calculus knowledge in tackling the problem.

Oerg
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Homework Statement


Ok, so I was doing a problem on the electric field strength of a continuous charge distribution and I arrived at this seemingly easy integral

\int \frac{1}{({l^2+a^2})^\frac{3}{2}} dl
sorry the latex is lagging badly, you can see the correct integral by clicking on it. it is 1/l squared + a squared with the denominator to the power of 3/2.

Homework Equations


The Attempt at a Solution


I do not know how to solve this... at all, and I am pretty sure that this integral is correct.
 
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Recheck your latex and include which variable you're integrating wrt.
 
This requires nothing more than a trig substitution.

l=a\tan\theta
dl=a\sec^{2}\theta d\theta

*\cos^2 x=\frac{1}{2}(1+\cos{2x})
 
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omggggg... this is killing me! wth invented integration

The final answer was supposed to be trigo free. Can you hint a little more, I am a little confused =x

btw it is supposed to be a definite integral from infinity to negative infinity.

oh yes, I am able to convert cos\theta and sin\theta to \frac{a}{(l^2+a^2)^\frac{1}{2}} or\frac{l}{(l^2+a^2)^\frac{1}{2}}PROVIDED

that \theta refers to the angle that (l^2+a^2)^{0.5} makes to the vertical.

By the way, this is a question of fidning the electric field strength of an infinitely long charged wire.
 
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You don't have to use trig sub., but I find it the easiest. Here is another thread with the exact problem you are doing except with different letters.

bob suggests to factor out the constant ... if you need more help post

https://www.physicsforums.com/showthread.php?t=220687
 
SIGHHHHHHHH

I guess I should start on my calculus 1 course first before attempting intro physics.Something i take comfort in though, I managed to come up with the electric field strength after I worked with the correct solution in the page your provided.
 
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Oerg said:
SIGHHHHHHHH

I guess I should start on my calculus 1 course first before attempting intro physics.
You haven't taken Calculus? Does this Intro course only require like a wimpy Intro or Elements to Calculus course?
 
nope, I am actualyl studying for my exemption test where I will get exempted rfom first course modules if I pass the tests.

I did study some calculus in high school which was required from the syllabus, either I am rusty, or they did not cover enough ground.
 
Oerg said:
nope, I'm actually studying for my exemption test where I will get exempted from first course modules if I pass the tests.

I did study some calculus in high school which was required from the syllabus, either I am rusty, or they did not cover enough ground.
What courses are in the "first course modules"?

Referring to Calculus: Trust me, it's worth taking the course. If you need more convincing, post in the Academic sub-forum. What you learn in a College Calculus course is far more in-depth than what you learned in HS.
 
  • #10
six modules in total:

Cal 1, linear algebra, diff equations

mechanics, Waves, EM
 
  • #11
Oerg said:
six modules in total:

Cal 1, linear algebra, diff equations

mechanics, Waves, EM
... You want to skip all those courses?
 
  • #12
If I could... Why not? I still have 5 months left,

Im done with mechanics which was easy, halfway through EM, guess i should start on Cal 1 soon.

oh yes, diff equations, I guess I will need them badly when doing electric potentials.
 

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