Intensity of light entering eye

AI Thread Summary
The discussion revolves around calculating the energy entering the eye from a 100-W lightbulb located 1.7 meters away, with only 5% of the bulb's power contributing to light. The user initially calculated the energy and intensity but found the results to be unreasonably high. They were advised to consider the power distribution over the surface area of a sphere surrounding the light source and to compare the area of the pupil to this sphere's area. The correct approach involves using the ratio of the pupil area to the sphere area to determine the power entering the eye, leading to a final answer of 2.7 microjoules. Clarification on the concept of power distribution and area ratios was requested to resolve the misunderstanding.
Weistber
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Hello all,
I came across this question in mastering physics and simply could not solve it. I asked for the answer to the question and decided to move on.

Homework Statement


You are standing 1.7m from a 100-W lightbulb.

If the pupil of your eye is a circle 5.0 mm in diameter, how much energy enters your eye per second? (Assume that 5.0% of the lightbulb's power is converted to light.)

Homework Equations


Energy of a beam of light =(Energy Density)(Volume):
U = UEM(Area X Speed Of Light X Change in time)
U = UEM(AcΔt)

Intensity:
I = U / (AΔt) = UEMc

The Attempt at a Solution



I decided that the energy of the beam must be equal to 5% of the wattage of the light bulb.

U = (5/100)*100W
= 5 J/s

I then found the energy density (UEM) by dividing U by volume (Area x distance from light source).

UEM = U / (AcΔt)
= (5) / (Pi((2.5*10^-3)^2) x 1.7)
= 149792.88 J/M^3

From this I derived the light intensity.
I = UEMc
= (149792.88) x (3 x 10^8)
= 4.49 x 10^13 J/s

At this point I was completely lost. The intensity is simply too large and has exceeded the amount of energy the light bulb can provide. I tried following through to the answer by multiplying intensity by area of the pupil, but the number was still far larger than the energy provided by the bulb. I tried using 5J as the value of UEM, but that didn't give the answer either.

The answer I received from mastering physics was 2.7 microjoules. Please explain to me the concept, I think I've misunderstood it and my notes aren't helpful at all. I don't need a worked answer, just an explanation of how I've misinterpreted the question or concept. Thank you, I'm starting to think I'm not cut out for this, spent three hours on such a simple question.
 
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You wrote,

U = (5/100)*100W
= 5 J/s

Let that power, call it P, fall uniformly on the inside of a sphere of radius 1.7m. What is the area of that sphere, call it A_s and call the area of your eye A_e. Those are the three numbers you have to deal with, P, A_s, and A_e. How should you combine those numbers to get the power in the eye, call it little p? You know little p will be much smaller then P and when you combine the numbers you must have units of power.
 
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