Intensity of sounds - Hearing Aid

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A hearing aid increases sound intensity by 50 dB, which corresponds to an intensity increase of 100,000 times. The relationship between intensity and amplitude indicates that intensity is proportional to the square of amplitude. To find the increase in amplitude, one must take the square root of the intensity increase. Therefore, the amplitude of the soundwave is increased by 316.23 times. This confirms the calculations regarding sound intensity and amplitude in relation to hearing aids.
whoknows123
A person wears a hearing aid, which makes a sounds louder by 50 dB. This a) means the sound intensity is increased by 100,000 times.
b) This also means that the amplitude of the soundwave is increased by ______ times?

I know Intensity is portportinal to (Amplitude)^2... so does that mean I squareroot the 100,000 times of the intensity to find part b?
 
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whoknows123 said:
A person wears a hearing aid, which makes a sounds louder by 50 dB. This a) means the sound intensity is increased by 100,000 times.
b) This also means that the amplitude of the soundwave is increased by ______ times?

I know Intensity is portportinal to (Amplitude)^2... so does that mean I squareroot the 100,000 times of the intensity to find part b?

Yes. Correct.
 
Yes.

- Warren
 

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