Interference by amplitude division (double reflection) for wedges

AI Thread Summary
The discussion focuses on a physics problem involving interference patterns created by light reflecting off a transparent wax layer on a glass plate. The angle α is calculated as approximately 0.001 radians based on the thickness and width of the wax. The participants debate the correct formula for determining the positions of bright fringes, with emphasis on the phase changes occurring upon reflection from different media. The consensus is that the total phase difference leads to bright fringes at specific thickness values, derived from the relationship d = kλ / (2n). The conversation highlights the importance of understanding phase shifts in optical interference.
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Homework Statement



Transparent wax of refractive index n=1.3 is deposited on top of a glass plate of width 1cm and refractive index n=1.5. The thickness of the wax is 0.01mm at one end of the plate and tapers uniformly to zero at the other end of the plate, which is defined to be at x=0. At this end the surface of the wax and of the glass form a small angle α. Light is incident on the plate from above, i.e. it goes through the wax, and is normal to the surface of the glass plate. Fringes are formed due to interference of light reflected from the top surface of the wax and from the glass.

i) Find the value of α.
ii) At what values of x do bright fringes occur if λ=520nm?

Homework Equations



Thickness of wedge, d = x tan(α) ≈ αx

The Attempt at a Solution



i) tan(α)=0.01/10 = 1×10-3 radians

ii) I'm not sure whether bright fringes occur at xn = ((ρ+0.5)λ)/2nα) or xn = (ρλ/2nα)
 
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You see the wedge from above. The bright fringes occur at those places where the phase difference between the ray reflected from the wax and that reflected from the glass makes integer times 2pi. The phase can change upon reflection and during traveling through a medium. The phase change upon reflection is pi when the wave arrives from a lower index medium to the surface of a higher index material, and it is zero in the opposite case. What is the phase change when the wave reflects from the wax and what is it when it reflects from the glass?

ehild
 
ehild said:
You see the wedge from above. The bright fringes occur at those places where the phase difference between the ray reflected from the wax and that reflected from the glass makes integer times 2pi. The phase can change upon reflection and during traveling through a medium. The phase change upon reflection is pi when the wave arrives from a lower index medium to the surface of a higher index material, and it is zero in the opposite case. What is the phase change when the wave reflects from the wax and what is it when it reflects from the glass?

ehild

Does that mean the phase change when light reflects from wax = pi and the phase change when light reflects from glass = pi?
How would I use this to find the values of x for which bright fringes occur?
 
Last edited:
As the phase changes at the interfaces cancel, the total phase difference is the phase shift inside the layer. It is
(4pi/λ) nd =2kπ,
where k is integer and d is the thickness of the layer. That means that bright fringes occur where the thickness is d=kλ /2n.

ehild
 
Thank you so much!
 
You are welcome.ehild
 
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