Interference from two radio antennae - simplistic and workings include

AI Thread Summary
The discussion revolves around the correct application of formulas for calculating minima and maxima in radio antenna interference. The initial confusion stems from miscalculating angles using the minima formula, leading to an incorrect result of 90 degrees for n=1. Participants clarify that the correct minima formula is 2λsinθ = mλ, with m taking non-integer values for minima. The user acknowledges their mistakes and expresses gratitude for the clarification, indicating they have now understood the concepts correctly. Accurate application of these formulas is essential for determining interference patterns in radio antennae.
elemis
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Is this correct ?

I have an issue for the minima formula when n=1 I get theta = 90 degrees.

This doesn't make any sense.

Is my method correct ?
 

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Your general method is correct, but your formula for the minima is incorrect. Check your notes or text.
 
TSny said:
Your general method is correct, but your formula for the minima is incorrect. Check your notes or text.

The formulas listed were in my notes.

Okay, for minima : 2λsinθ = mλ m=0.5,1.5,2.5,3.5...

This would give me the required non-integr half wavelengths for a minima, correct ?

EDIT : Hence m =0.5 would mean the first minima is at 30 degrees.

maxima : 2λsinθ = nλ n = 0,1,2,3,4,5...

For n =1 I still get theta to be 90 degrees... I don't see what I'm doing wrong.
 
Your minima formula is wrong.
 
rude man said:
Your minima formula is wrong.

Can you check the post above yours, please ?
 
elemis said:
The formulas listed were in my notes.

Okay, for minima : 2λsinθ = mλ m=0.5,1.5,2.5,3.5...

This would give me the required non-integr half wavelengths for a minima, correct ?

EDIT : Hence m =0.5 would mean the first minima is at 30 degrees.
No. 2sin(theta) = 0.5 does not yield theta = 30 deg.

maxima : 2λsinθ = nλ n = 0,1,2,3,4,5...

For n =1 I still get theta to be 90 degrees... I don't see what I'm doing wrong.

No. 2sin(theta) = 1 does not yield theta = 90 deg.
 
rude man said:
No. 2sin(theta) = 0.5 does not yield theta = 30 deg.



No. 2sin(theta) = 1 does not yield theta = 90 deg.

Ah, God, silly mistakes... Forgive my lapse in concentration. Its pretty late where I am right now.

I've understood this question now. Thank you.
 
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