Internal resistance of cells in parallel

AI Thread Summary
The discussion addresses the equivalent resistance of three identical cells connected in parallel, noting that the internal resistance is divided by three. It highlights confusion regarding why the electromotive force (emf) remains that of a single cell despite the simplified resistance calculation. Participants seek a thorough explanation of this phenomenon, particularly in the context of internal resistance in batteries. The inquiry emphasizes the need for clarity on how emf and resistance interact in parallel configurations. Understanding these principles is crucial for effective battery management and application.
abcd8989
Messages
44
Reaction score
0
I know, as a matter of fact, that the equivalent resistance of three identical cells in parallel is equal to the internal resistance devided by 3. When we are concerning simply 3 equal resistors in parallel, I know that the outcome resistance is what. But when it comes to three cells with internal resistance, I don't understand why the emf is that of one cell and the resistance could be resolved so simply . Would anyone please give me a thorough explain on that? Much obliged!
 
Physics news on Phys.org
[PLAIN]http://dl.dropbox.com/u/4222062/Parallel%20batteries.PNG
 
Last edited by a moderator:
Thread 'Motional EMF in Faraday disc, co-rotating magnet axial mean flux'
So here is the motional EMF formula. Now I understand the standard Faraday paradox that an axis symmetric field source (like a speaker motor ring magnet) has a magnetic field that is frame invariant under rotation around axis of symmetry. The field is static whether you rotate the magnet or not. So far so good. What puzzles me is this , there is a term average magnetic flux or "azimuthal mean" , this term describes the average magnetic field through the area swept by the rotating Faraday...
Back
Top