Internal vs external force - conservation of momentum in one dimension

AI Thread Summary
In the collision experiment involving gliders A and B on a frictionless surface, glider A initially moves to the right while glider B is at rest with a compressed spring. When the spring is released upon contact, glider A moves to the left with a speed greater than its initial velocity. The discussion centers on whether the momentum of the system at the final time is greater than, less than, or equal to the initial momentum. It concludes that the momentum remains conserved, as the forces involved are internal to the system of gliders, meaning the total momentum does not change despite the impulse from the spring. Thus, the magnitude of momentum at time t(f) is equal to that at time t(i).
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Homework Statement



This problem concerns a collision experiment performed on a frictionless surface with gliders A and B, with masses m(a) and m(b) respectively.

In a level track, glider B has a spring-loaded plunger attached to it. At time t(i), glider A moves to the right with speed v(0), and glider B is at rest. The plunger is initially compressed, and it is released when the gliders come into contact. At time t(f), glider A moves to the left with speed greater than v(0).

Is the magnitude of the momentum of the system of the two gliders at time t(f) greater than, less than or equal to the magnitude of the momentum of the system at time t(i)? Explain.

Homework Equations



F=ma
conservation of momentum : mivi = mfvf

The Attempt at a Solution



At first I thought that this the momentum of the system at t(f) must be greater than at t(i), because the plunger "pushes" A, adding an extra force to glider A, (this would be the impulse, so change in momentum added to the glider?). But would this force be counted as an internal force versus an external force instead, and so momentum is conserved?
 
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The system comprises the two gliders which only "push" against each other, nothing else. You can't make a reactionless rocket so I'd say the total system momentum is the same.
 
Thanks! That makes sense.
 
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