Interpreting Hall Effect Equation Physically: B & V

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The discussion focuses on interpreting the Hall Effect equation, particularly the relationship between magnetic field strength (B) and Hall voltage (V). An increase in B leads to a higher V due to the Lorentz force acting on charge carriers, which is defined by the equation F=qv×B. The drift velocity of charge carriers is influenced by carrier density (n) and charge (e), with lower carrier density resulting in higher drift velocity for a given current. The Hall voltage is directly related to the Lorentz force, which depends on the velocity of the charge carriers. Understanding these relationships is crucial for determining factors that affect Hall voltage in conductors.
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how to interpret this equation physically?
Why increase of B will lead to increase of V?
Similar to I,n,e and t
thx a lot
 
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The force on the charge carriers in the current is ##\vec{F}=q\vec{v}\times\vec{B}## - if the charge carriers are constrained to move in a conductor, what happens?
 
Simon Bridge said:
The force on the charge carriers in the current is ##\vec{F}=q\vec{v}\times\vec{B}## - if the charge carriers are constrained to move in a conductor, what happens?

i got how to interpret B and e maybe
But for n and t,why would it matter the V?
 
For a given current, the drift velocity of the carriers is higher if you have lower carrier density (n).
Actually, if you have lower values of n*e.
And the Hall voltage depends on the Lorentz force which depends on the velocity.
 
asdff529 said:
i got how to interpret B and e maybe
But for n and t,why would it matter the V?
The V is the voltage developed across the "width" of the conductor as a result of the lorentz force. V is what the equation is trying to find.

So work it out - what makes V bigger? What makes V smaller?
 

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