Interpreting Velocity Components in a Non-Head On Collision

AI Thread Summary
In a non-head-on collision between two equal mass balls, the initial vertical momentum is zero, leading to a final y-component of velocity that must also sum to zero. This implies that the y-components of the velocities of both balls must be equal in magnitude but opposite in direction after the collision. The question does not provide numerical values, so the focus should be on the relationship between the velocities rather than specific magnitudes. The direction of the y-component for one ball will be positive and for the other will be negative, ensuring momentum conservation. Understanding these relationships is key to interpreting the problem correctly.
twofish
Messages
24
Reaction score
0
Hi all,
I'm new here and am having a problem interpreting a homework question, hope i can explain it correctly.
The question is below.

"One ball goes along the x-axis and collides with a stationary ball of equal mass in a collision that is not head on. How does the y component of each velocity compare afterwards? Give both magnitude and direction."

My answer thus far is;
"When ball A is rolling along the x-axis there is no initial vertical momentum or y component, therefore the vector sum of the final vertical (Y) components of the two balls must be zero. "

What's got me hung up is the magnitude and direction part of the question.
Since I'm not really given any numbers to work with I'm unsure how to answer the second part of the question.
Can I assume that they are looking for the magnitude of the velocity, in which case I would answer v`a = (p`a)/(ma) for ball a, and similar for ball b.
Or do they want the magnitude of the vectors, in which case I would have to incorporate cos θ = (p`a)/p` and sin θ = (p`b)/p`
Thanks,
 
Last edited:
Physics news on Phys.org
You're absolutely right that the y-component of the momentum must be zero. Now - you have two balls of equal mass. What can you say about the y-component of their velocities (both the magnitude and the direction) if the y-momentum is to cancel out? Note: You won't be able to give a numeric answer for the speeds, but you can say how they compare. Hint hint.
 
Last edited:
Hrm ..okie, well I'll try working that angle.
Thanks much!
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top