MHB Introductory Algebra Percentage Word Problem

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The discussion revolves around a percentage word problem involving a dress marked down first by 20% and then by an additional 15%, resulting in a final price of $51. The initial calculations incorrectly added the discount percentages, leading to a misunderstanding of the final sale price as 65% of the original price. The correct approach shows that after both discounts, the final price is actually 68% of the original price. The original price is calculated to be $75, not $78.46, confirming that the book's answers are accurate. Understanding the sequential nature of percentage reductions is crucial for solving such problems correctly.
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The problem as given in the book:

The price of a dress is marked down 20% on May 1. On May 25th the reduced price is marked down an additional 15% to \$51. (a) What percent of the original price is the final sale price? (b) "What is the original price?

All I could think was trying to work the problem this way:

(a) 20% + 15% = 35% (total discount percentage)
100% - 35% = 65% (percent of the original price for a sale price of \$51)

(b) 65%x = \$51
x = 51/.65
x = \$78.46 (original price)

The answer given in the back of the book is given as (a) 68% and (b) \$75. Assuming the book's answer is correct, what am I missing?

- - - Updated - - -

Er, it posted all garbled for some reason. I have no idea why. Any ideas?
 
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Larry2527 said:
The problem as given in the book:

The price of a dress is marked down 20% on May 1. On May 25th the reduced price is marked down an additional 15% to \$51. (a) What percent of the original price is the final sale price? (b) "What is the original price?

All I could think was trying to work the problem this way:

(a) 20% + 15% = 35% (total discount percentage)
100% - 35% = 65% (percent of the original price for a sale price of \$51)

(b) 65%x = \$51
x = 51/.65
x = \$78.46 (original price)

The answer given in the back of the book is given as (a) 68% and (b) \$75. Assuming the book's answer is correct, what am I missing?

Let $P$ be the original price.

first reduction to $0.80P$

second reduction to $0.85(0.80P) = 0.68P = 51 \implies P = 75$

the final price is 68% of $P = 75$

fyi, dollar signs activate the latex math type on this site. if you want to use one without doing so, put a backward slash \ prior to the dollar sign.
 
Larry2527 said:
The problem as given in the book:

The price of a dress is marked down 20% on May 1. On May 25th the reduced price is marked down an additional 15% to \$51. (a) What percent of the original price is the final sale price? (b) "What is the original price?

All I could think was trying to work the problem this way:

(a) 20% + 15% = 35% (total discount percentage)
There is your mistake! A percentage is always a percent of something (the "base" number). You cannot add these percentages because they are of different bases. The first is 20% of the original price. The second is 15% of that new price.

Let P be the original price. Then after the first mark down, the price is P'= P- 0.20P= 0.80P. After the second markdown, the price is P'- 0.15P'= 0.85P'= 0.85(0.80P)= 0.68P, or 68% of the original price, not 65%.

0.68P= 51 so P= 51/0.68

100% - 35% = 65% (percent of the original price for a sale price of \$51)

(b) 65%x = \$51
x = 51/.65
x = \$78.46 (original price)

The answer given in the back of the book is given as (a) 68% and (b) \$75. Assuming the book's answer is correct, what am I missing?

- - - Updated - - -

Er, it posted all garbled for some reason. I have no idea why. Any ideas?
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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