Intuitive statistical mechanical explanation for thermodynamic 2nd law

In summary: I don't like to look at it that way. As I see it, classical thermodynamics and the four laws are a concise statement of experimental results. Equilibrium is defined in classical thermodynamics. Statistical mechanics then comes along and explains classical thermodynamics. Stat. mech. says, look, the system can be in any of a huge number of microstates, and the overwhelming majority of those states correspond to the macrostate that classical thermodynamics calls equilibrium - the equilibrium macrostate. Questions like "why are almost all microstates equilibrium microstates" is then a statistics problem, and a good question. The fact that systems at equilibrium almost always stay in equilibrium suggests that each microstate is equally likely.A finer point is the
  • #1
vinovinovino
2
0
I don't have the intuitive picture of thermodynamic 2nd law, in terms of statistical mechanics. That is, why should the number of microstates be maximized in equilibrium? Anyone gives an intuitive explanation? Thanks a lot.
 
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  • #2
vinovinovino said:
I don't have the intuitive picture of thermodynamic 2nd law, in terms of statistical mechanics. That is, why should the number of microstates be maximized in equilibrium? Anyone gives an intuitive explanation? Thanks a lot.

Its not that the number of microstates is maximized in equilibrium. You have a fixed number of microstates, and most of those microstates are equilibrium microstates. The system bounces around among those microstates, and since almost all of them are equilibrium microstates, the system is almost always in an equilibrium microstate.

The real question is, why are almost all microstates equilibrium microstates? You can get an intuitive feel for this by considering a deck of cards - why, after I shuffle a deck of cards, are the red suits and the black suits more or less evenly distributed throughout the deck? The more or less even distribution corresponds to equilibrium.

The number of ways you can arrange the cards in a deck (the microstate) is a fixed number. Almost all of them will have the red and black suits more or less evenly distributed (equilibrium macrostate). Only a small number will have a lot of black cards in the top half and a lot of red cards in the bottom half. (non-equilibrium macrostate).
 
  • #3
Rap said:
Its not that the number of microstates is maximized in equilibrium. You have a fixed number of microstates, and most of those microstates are equilibrium microstates. The system bounces around among those microstates, and since almost all of them are equilibrium microstates, the system is almost always in an equilibrium microstate.

The real question is, why are almost all microstates equilibrium microstates? You can get an intuitive feel for this by considering a deck of cards - why, after I shuffle a deck of cards, are the red suits and the black suits more or less evenly distributed throughout the deck? The more or less even distribution corresponds to equilibrium.

The number of ways you can arrange the cards in a deck (the microstate) is a fixed number. Almost all of them will have the red and black suits more or less evenly distributed (equilibrium macrostate). Only a small number will have a lot of black cards in the top half and a lot of red cards in the bottom half. (non-equilibrium macrostate).

Well that's one way to go about it, but it seems rather backward. IMO it would make more sense to define equilibrium as the macrostate with the most number of microstates corresponding to it. Then questions like "The real question is, why are almost all microstates equilibrium microstates" get tautological answers, and it becomes really evident to see why a system is most likely in its equilibrium state, as it follows directly from the definition of equilibrium and the plausible guess that every microstate is equally likely.
 
  • #4
mr. vodka said:
Well that's one way to go about it, but it seems rather backward. IMO it would make more sense to define equilibrium as the macrostate with the most number of microstates corresponding to it. Then questions like "The real question is, why are almost all microstates equilibrium microstates" get tautological answers, and it becomes really evident to see why a system is most likely in its equilibrium state, as it follows directly from the definition of equilibrium and the plausible guess that every microstate is equally likely.

I don't like to look at it that way. As I see it, classical thermodynamics and the four laws are a concise statement of experimental results. Equilibrium is defined in classical thermodynamics. Statistical mechanics then comes along and explains classical thermodynamics. Stat. mech. says, look, the system can be in any of a huge number of microstates, and the overwhelming majority of those states correspond to the macrostate that classical thermodynamics calls equilibrium - the equilibrium macrostate. Questions like "why are almost all microstates equilibrium microstates" is then a statistics problem, and a good question. The fact that systems at equilibrium almost always stay in equilibrium suggests that each microstate is equally likely.

A finer point is the difference between the idea that 1) the number of microstates corresponding to the equilibrium macrostate is larger than the number of microstates for any other macrostate and 2) the number of microstates corresponding to the equilibrium macrostate is OVERWHELMINGLY larger than the number of microstates for any other macrostate. This is the difference between saying that the system will be in an equilibrium macrostate most often, and that it will be in an equilibrium macrostate almost always.

The real question is why is it OVERWHELMINGLY larger, not just larger. Why is the equilibrium microstate not simply the most common, but almost the only one? Thats a good statistical question, and answering it will address the OP, I think.
 
  • #5
Well your first paragraph seems to be a matter of taste. I like to give precedence to the concepts of statistical mechanics, as they apply more broadly. Analogously, I don't like to see the Boltzmann entropy as an explanation for thermodynamic entropy, rather I like to see the latter as a specific application of the former.

As for your other paragraphs, I agree!
 
  • #6
mr. vodka said:
Well your first paragraph seems to be a matter of taste. I like to give precedence to the concepts of statistical mechanics, as they apply more broadly. Analogously, I don't like to see the Boltzmann entropy as an explanation for thermodynamic entropy, rather I like to see the latter as a specific application of the former.

As for your other paragraphs, I agree!

Well, you are probably right about it being a matter of taste, but I like to keep clear in my mind the difference between a phenomenological theory and an explanatory theory. I think classical thermodynamics and Maxwell's equations, for example, are phenomenological - they are a condensed description of experimental results which make very little use of untestable abstractions - they are expressed in terms of measurements. The explanatory theories, like statistical mechanics, or quantum mechanics make use of untestable or unmeasureable abstractions like the microstate, or the wave function. I don't like to confuse the two, and I take the phenomenological theories as the bottom line, while the explanatory theories are not to be believed in a religious sense.

I also take issue with the idea that classical thermodynamic entropy is a specific application of Boltzmann (or information) entropy. Classical thermodynamic entropy is defined in terms of concrete macroscopic measurements, making no reference to microstates or probabilities or statistics. It does not speak the language of statistical mechanics, while statistical mechanics DOES speak the language of classical thermodynamics. Statistical mechanics explains thermodynamic entropy, but thermodynamic entropy is not an application of any statistical concept.
 

1. What is the second law of thermodynamics?

The second law of thermodynamics states that in any natural process, the total entropy of a closed system will either remain constant or increase. This means that the total disorder or randomness of a system will always tend to increase over time.

2. How does statistical mechanics explain the second law of thermodynamics?

Statistical mechanics uses the principles of probability and statistics to describe the behavior of large groups of particles, such as molecules in a gas. It explains the second law of thermodynamics by showing that the tendency towards disorder or entropy increase is a result of the statistical behavior of these particles.

3. What is an intuitive explanation for the second law of thermodynamics?

An intuitive explanation for the second law of thermodynamics is that energy tends to disperse and become more evenly distributed over time. This is because there are many more ways for energy to be randomly distributed than to be concentrated in a specific way, leading to an overall increase in disorder.

4. How does the concept of entropy relate to the second law of thermodynamics?

Entropy is a measure of the disorder or randomness of a system. The second law of thermodynamics states that the total entropy of a closed system will either remain constant or increase. This means that the natural tendency towards increasing entropy is a fundamental aspect of the second law.

5. Can the second law of thermodynamics be violated?

The second law of thermodynamics is a fundamental law of nature and has not been observed to be violated. While it is theoretically possible for the entropy of a closed system to decrease, the probability of this happening is extremely low and has never been observed in practice.

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