Inverse fourier transform of constant

lemonsie
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Homework Statement


Find the inverse Fourier transform of f(w)=1 Hint: Denote by f(x) the inverse Fourier transform of 1 and consider convolution of f with an arbitrary function.


Homework Equations



From my textbook the inverse Fourier transform of f(w)=\int F(w)e^-iwt dw


The Attempt at a Solution



Ive tried letting f(x) be the Fourier transform of 1 and convolving it with an arbitrary function g(x) but for some reason this leads me nowhere.
 
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lemonsie said:

Homework Statement


Find the inverse Fourier transform of f(w)=1 Hint: Denote by f(x) the inverse Fourier transform of 1 and consider convolution of f with an arbitrary function.


Homework Equations



From my textbook the inverse Fourier transform of f(w)=\int F(w)e^-iwt dw


The Attempt at a Solution



I've tried letting f(x) be the Fourier transform of 1 and convolving it with an arbitrary function g(x) but for some reason this leads me nowhere.
Precisely what sort of nowhere do you get to?
 
i let f(x)= Inverse Fourier transform of 1, which from the formula i have gives f(x)=∫e^-iwx dw

then using the convolution formula with my f(x) above and the aribitrary function g(x) i get

f*g(x) = ∫e^-iwx dw ∫ g(x-t) dt

the integrals have bounds -∞ to ∞
 
ive got it solved now. thanks anyways sammy! :)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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