(adsbygoogle = window.adsbygoogle || []).push({}); matlab:

>> ilaplace(exp(-1*s)/(s+3)^3)

ans =

1/2*heaviside(t-1)*(t-1)^2*exp(-3*t+3)

But I think there should be an additional exp(3) multiplied by all.

=exp(-1*s)/(s+3)^3

=exp(-1*(s+3)+3)/(s+3)^3

Taking out exp(-3t). In above step I did (s+3)+3 because exp(-3t) says all variables should be shifted by 3 ..

=[exp(-1*(s)+3)/(s)^3]*exp(-3t)

Now I take care anything but Heaviside

=[exp(-1*(s))]*exp(-3t)*[t^2/2]*exp(3)

now I take care of Heaviside

=exp(-3(t-1))*[(t-1)^2/2]*exp(3)

I might have made some error while explaining what I was doing - just ignore it. But, the thing I am concerned about is the one in red. It gives me exp(3) in the end which matlab does not.

Thanks

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# Homework Help: Inverse Laplace transform of ex(-s)/(s+3)^3

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