How do I find the inverse of a log function?

In summary, you tried to solve equations for x, changed the base, and swapped x and f(x). You then tried to find the inverse, but were unsuccessful.
  • #1
hancyu
57
0

Homework Statement



f(x) = log2 x + 3
2 log2 x − 1
how do i find the inverse of this? how do i find the range and domain of a log function?

Homework Equations

f(x) = log2 x + 3
2 log2 x − 1

is equal to
f(x) = log2 x + 3 - log2 (x − 1)2

D of f(x) = R of f-1(x)

The Attempt at a Solution



i tried changing the base but it didnt work...
 
Last edited:
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  • #2
also, is the inverse of

f(x) = 2x−1 + 3

log2 (x/3) +1 = y


f(x) = log2/3(x − 2) − 4

(2/3)x+4 + 2 = y

are these correct?
 
  • #3
Ok. Your attempt was sadly, incorrect, although similar to something you were probably thinking of:

[tex]\log_c ( \frac{a}{b} ) = \log_c a - \log_c b[/tex],

which is not the same as what you tried: [tex] \frac{ \log_c a}{\log_c b} = \log_c a - \log_c b[/tex], which is not true.

It might help if you let [itex]u= log_2 x[/itex] so that you may view the problem easier. Doing so, solve the equation you have for you, replace the expression in x back in and solve it for x. Then swap your x and f(x), that's your inverse function!

For your second problem, not quite. Solve it for x first. So First take 3 to the other side,

[itex]2^{x-1} = f(x) - 3[/itex]. After that, take log_2 of both sides, hopefully you can see the rest. Then just swap x for f(x).

The last one looks correct, good work =]
 
  • #4
Presumably you know that the domain and range of any function of the form loga(x) is {x|x> 0} and all real numbers respectively.

You also should know that the domain of a rational function is all numbers such that the denominator is not zero.

Putting those together, the domain of loga(f(x))/loga(g(x)) is all x such that x is positive and g(x) is not 1 (so that log(g(x)) is not 0).
 
  • #5
HallsofIvy said:
Presumably you know that the domain and range of any function of the form loga(x) is {x|x> 0} and all real numbers respectively.

You also should know that the domain of a rational function is all numbers such that the denominator is not zero.

Putting those together, the domain of loga(f(x))/loga(g(x)) is all x such that x is positive and g(x) is not 1 (so that log(g(x)) is not 0).

so the domain of the 1st one is x=>0 ? because log can never be zero or negative?

i still can't get the inverse tho...
 

1. What is the inverse of a log function?

The inverse of a log function is an exponentiation function. In other words, it is the function that "undoes" the action of taking a logarithm. For example, if the original log function is loga(x), the inverse function would be ax.

2. How do you find the inverse of a log function?

To find the inverse of a log function, you can use the "change of base" formula, which states that loga(x) = logb(x) / logb(a). This allows you to convert the base of the logarithm to any other base, making it easier to find the inverse function.

3. What is the domain and range of the inverse log function?

The domain of the inverse log function is all real numbers, except for 0. This is because the base of a logarithm cannot be 0. The range of the inverse log function is also all real numbers, as the output of a logarithm can be any real number.

4. Can you graph the inverse of a log function?

Yes, the inverse of a log function can be graphed. The graph of the inverse function will be the reflection of the original log function's graph over the line y = x. This is because the inverse function "undoes" the action of the original function.

5. How is the inverse of a log function used in real life?

The inverse of a log function has many practical applications in fields such as finance, biology, and physics. For example, it can be used to calculate the growth rate of a population, the half-life of a radioactive substance, or the interest rate on a loan. It is also used in data analysis and modeling to transform data that follows an exponential pattern into a linear form.

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