Inverse Square Law: Solving a Question with Door Dimensions

[dura]

I had a question regarding a sound with a given Intensity and a given radius (say 0.1m from point source) that travels through a door with dimensions given as well. It also gives a second radius (say 30m from point source) and asks what the acoustic power was at a second radius after traveling through the door.

I know I am using the inverse square law to relate the second intensity, but how do I figure the door into the question?

Im sorry I can't give the exact question, it was in a quiz and I don't have any similar examples with me. I am trying to remember the question off the top of my head.

Any help would be excellent.

Regards,
Julie

 

[Nate810]

In order to answer this question, you will need to consider the acoustic properties of the door and how it affects the sound passing through it. Depending on the material of the door, its thickness, and any other features which may influence the sound, you may need to calculate the attenuation of the sound as it passes through the door. This can be done using various formulas for sound absorption, transmission loss, and/or reflection loss. Once you have calculated the attenuation, you can use the inverse square law to calculate the intensity at the second radius.

 

[wais]

Hi Julie,

The inverse square law states that the intensity of a sound wave decreases with the square of the distance from the source. In this case, we can use this law to relate the intensity at the first radius (0.1m) to the intensity at the second radius (30m).

To incorporate the door dimensions into the question, we need to consider the door as a barrier that the sound wave must pass through. The door will absorb some of the sound energy and thus decrease the intensity of the sound wave. This can be represented by a transmission coefficient, which is the ratio of the intensity of the sound wave after passing through the door to the intensity before passing through the door.

To solve this question, we can use the following formula:

I2 = I1 * (r1/r2)^2 * T

Where I1 is the intensity at the first radius, r1 is the distance from the source to the door, r2 is the distance from the source to the second radius, and T is the transmission coefficient.

To find the acoustic power at the second radius, we can use the following formula:

P2 = P1 * (r1/r2)^2 * T

Where P1 is the acoustic power at the first radius and P2 is the acoustic power at the second radius.

I hope this helps you solve the question. If you need any further assistance, please let me know.