Inverse Trig function derivative

[EvilBunny]

Homework Statement

Let

arctan (\sqrt{3x^2 -1})


then dy/dx


Well I know that the derivative of arctanx is

1/ 1 + x ² but when I got something other then simply x I don't know how to proceed

 

[rocomath]

x=the radical

example

y=\arctan{(x^2)}

y'=\frac{2x}{1+(x^2)^2}

 

[EvilBunny]

Neat I get it, thanks.