ok this is how i got 10 degrees and the Fnet:
Step #1: Use the cosine law to solve for the magnitude of the net force
c2 = a2 + b2 – 2abcosC
c2 = (800 N)2 + (400 N)2 – 2(800 N)(400 N)cos150 degrees
c = 1165 NStep #2: Use the sine law to solve for the angle of the net force
SinB/b = SinC/c
SinB/400 N = Sin150 degrees/1165 N
b = sin-1 (400 N x Sin150o/1165 N)
b = 9.8 » 10 degrees
To determine the angle for the net force, subtract 20 fromb, as this results in the angle needed to describe the direction of the net force.
20 degrees – 10 degrees = 10 degrees
Fnet = 1165 N [N 10 degrees W] it can also be looked at as 10.2 degrees, i just rounded 9.8 to 10 exactly.
The net force on the log is 1165 N at an angle of 10 degrees west of north.