Investigating Weak Gravitational Field in India/Indian Ocean

AI Thread Summary
The weak gravitational field at the bottom of India and the Indian Ocean is linked to the unique tectonic activity resulting from the convergence of the Indian and Eurasian plates, which has created the Himalayas and contributed to a gravitational anomaly. The geoid level in this region dips closer to the Earth's center, indicating an anomalous density structure beneath India. This phenomenon does not necessarily imply that gravity is stronger or weaker at the surface, as gravity is a measure of the local gradient of the gravitational potential field. The geoid map reflects the gravitational potential relative to a reference ellipsoid, showing that lower geoid levels correspond to areas of lower gravitational potential. The discussion also touches on the idea that fluid dynamics in the Earth's mantle may respond to gravitational anomalies, leading to variations in surface levels. Overall, the gravitational anomaly suggests a denser structure beneath the Indian Ocean, which may influence local gravitational effects.
curiousphoton
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Well, you can rule out crustal thickness.
http://earthquake.usgs.gov/research/structure/crust/images/topo.jpg" of crustal thickness shows that Indonesia (which has a high geoid level) and the Indian Ocean (which has the mysteriously low geoid level) have similar crustal thicknesses.

Tectonics must have something to do with it. The Indian-Eurasian plate convergence is unique in a lot of ways. It has given rise to the Himalayas, and is now apparently home to a gravitational anomaly. The areas with a low geoid level seem to all be on actively subducting plates. The high geoid levels tend to be near spreading centers. Hmm... I fail to see a connection, though...
 
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Curiosphoton, careful with your interpretation of the map there. If you look at the scale bar you will see that it has units of meters. But gravity has units of acceleration. So what is that map really showing?

That map is showing the level of the geoid (the surface defined as having equal gravitational potential) relative to a datum, a reference ellipsoid.

We can say that each point at any given latitude on the reference ellispoid is the same distance from the center of the Earth as any other point on that latitude. And if we had a layered Earth with a perfectly symmetric density structure (about the pole-axis) then the gravitational potential would sit exactly flat on the reference ellipsoid. But we see that at India the geoid dips down closer to the centre of the Earth. This does not mean incidentally that gravity is stronger or weaker at that location (although it would tend to make me think it is stronger there), because g is a measure of the local gradient of the potential field which we cannot measure given only one equipotential surface. But it does mean that something in Earth's density structure is anomalously dense below India.
 
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billiards said:
But it does mean that something in Earth's density structure is anomalously dense below India.

Would you expect a higher or lower density below India? If I understand it correctly, the graph depicts the theoretical shape of the earth, when there was no vertical structure, say when the Earth was fluid.

Now. if there is a stronger gravity anomaly somewhere, you'd expect that fluid to move towards that anomaly causing a higher surface locally, an idea of Nils Axel Morner. So, as an analogy, I'd expect the fluid to flow away from a weaker local gravity, causing a lower lever locally.
 
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billiards said:
Curiosphoton, careful with your interpretation of the map there. If you look at the scale bar you will see that it has units of meters. But gravity has units of acceleration. So what is that map really showing?

That map is showing the level of the geoid (the surface defined as having equal gravitational potential) relative to a datum, a reference ellipsoid.

We can say that each point at any given latitude on the reference ellispoid is the same distance from the center of the Earth as any other point on that latitude. And if we had a layered Earth with a perfectly symmetric density structure (about the pole-axis) then the gravitational potential would sit exactly flat on the reference ellipsoid. But we see that at India the geoid dips down closer to the centre of the Earth. This does not mean incidentally that gravity is stronger or weaker at that location (although it would tend to make me think it is stronger there), because g is a measure of the local gradient of the potential field which we cannot measure given only one equipotential surface. But it does mean that something in Earth's density structure is anomalously dense below India.

I disagree. If you look at the colored map up top, the meters refers to the distance between Earth's flattened sphere (see note 1 on the diagram 'mapping the different effects of gravity') and the geoid (note 3). The smaller the distance, the weaker the gravitational field...hence my original question.
 
The elevations over the oceans are reflective of winds and currents.
 
Xnn said:
The elevations over the oceans are reflective of winds and currents.

Um doesn't the article say that this is what the ocean would look like with no winds and currents and only the effect of gravity. See the main diagram in the middle of the article for more...
 
Andre said:
Would you expect a higher or lower density below India? If I understand it correctly, the graph depicts the theoretical shape of the earth, when there was no vertical structure, say when the Earth was fluid.

Now. if there is a stronger gravity anomaly somewhere, you'd expect that fluid to move towards that anomaly causing a higher surface locally, an idea of Nils Axel Morner. So, as an analogy, I'd expect the fluid to flow away from a weaker local gravity, causing a lower lever locally.

Agreed. The implication of that is that g is betrayed (at least in its relative "anomaly" sense) by the shape of the equipotential surface, which is a consequence I haven't quite got my head around yet. Back to the books for me! I guess if mass goes from high gravitational potential to low gravitational potential and at some level beneath India the equipotential surface smooths out then g (being the gradient of potential) must be weaker where the surface was at a mimimum higher up??
 
Maybe an important factor is that the (local) surface of a fluid (assuming equilibrium) is perpendicular to the (local) gravity vector, regardless of the value of that vector.
 
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