Irrational sequence that converges to a rational limit

cnwilson2010
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Hi. I found some rational sequences that converge to irrational limits, but am not having any luck going the other direction, i.e., an irrational sequence that converges to a rational limit. Any suggestions?
 
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Can you find an irrational sequence that converges to 0? Something like \frac{1}{n} but with an irrational number in the numerator?
 
Thank you.

How about 1/n(2(1/2))?
 
cnwilson2010 said:
Thank you.

How about 1/n(2(1/2))?

Yes, that sounds good! :smile:
 
You can also use a commonly known irrational number (e.g. pi or e) and do something similar.
 
Didn't want to be oddly transcendental or anything, so I was trying to stay away from those, but found out later they would have been fine. So thank you for that.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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