Is 1D Space a Subspace of 2D Space in Physics?

gianeshwar
Messages
225
Reaction score
14
Please excuse me for my less knowledge. I always tried to physically visualise mathematics facts.
My first question is " Is 1D space of physics a subspace of 2D space of physics and so on...
So in this way our 3D space is a subspace of 4 D space(spacetime).
Can I imagine applying all properties of vector space applicable in physical world?
My study of Advanced Algebra is still in infancy.
Please let me know if my question is irrelevant.
Thank you all in advance.
Please reply so that I start further discussion related to Advanced Algebra. I want to master it.

In classical mechanics some process can be defined in terms of generalised coordinates like density , temperature , location , time and so on...
Now a space is defined with independent dimensions density,temperature,location, time and suppose colour.
Is space generated by density, temperature and location a subspace of above space.
Is it embedded in the above space?
Can I have two different subspaces of five dimensions of the above space?
 
Last edited:
Physics news on Phys.org
If n < m, then n dimensional space can be considered a subspace of m dimensional space.
Example: Let{(x,y,z)|x,y,z real} be a 3 dimensional space. Then {(x,y,a)|x,y real, a fixed} is a 2 dimensional subspace for each value of a.

I think this should help you with the second question. You can have as many subspaces as you want.
 
Notice the difference between your question "Is 1D space of physics a subspace of 2D space of physics and so on... So in this way our 3D space is a subspace of 4 D space(spacetime)."

and mathman's response "If n < m, then n dimensional space can be considered a subspace of m dimensional space."

Strictly speaking, no, 1D space is NOT a subspace of 2D space and 3D space is not a subspace of 4Dspace. Points in 1D space can be designated by a single number, a, while points in 2D space are designated by pairs of numbers, (x, y). But we can associate the point, a, with the pair (a, 0) so there is an "isomorphism" between 1D and a subspace of 2D. This is NOT the same as saying 1D is a subspace itself because there are many different such "isomorphisms" or assignments: a with (0, a) or with (a, a) or (a, ma) for fixed m, etc.
 
Thank you dear friends!
 
To a large extent physics in the plane can be considered a super position of physics on two lines. However, be careful. Special relativity with physics in 4 D (Space-time) is like physics in conventional four dimensions except the metric is different. The interval in special relativity is (often): sqr root(x squared + y squared + z squared - time squared).
 
##\textbf{Exercise 10}:## I came across the following solution online: Questions: 1. When the author states in "that ring (not sure if he is referring to ##R## or ##R/\mathfrak{p}##, but I am guessing the later) ##x_n x_{n+1}=0## for all odd $n$ and ##x_{n+1}## is invertible, so that ##x_n=0##" 2. How does ##x_nx_{n+1}=0## implies that ##x_{n+1}## is invertible and ##x_n=0##. I mean if the quotient ring ##R/\mathfrak{p}## is an integral domain, and ##x_{n+1}## is invertible then...
The following are taken from the two sources, 1) from this online page and the book An Introduction to Module Theory by: Ibrahim Assem, Flavio U. Coelho. In the Abelian Categories chapter in the module theory text on page 157, right after presenting IV.2.21 Definition, the authors states "Image and coimage may or may not exist, but if they do, then they are unique up to isomorphism (because so are kernels and cokernels). Also in the reference url page above, the authors present two...
When decomposing a representation ##\rho## of a finite group ##G## into irreducible representations, we can find the number of times the representation contains a particular irrep ##\rho_0## through the character inner product $$ \langle \chi, \chi_0\rangle = \frac{1}{|G|} \sum_{g\in G} \chi(g) \chi_0(g)^*$$ where ##\chi## and ##\chi_0## are the characters of ##\rho## and ##\rho_0##, respectively. Since all group elements in the same conjugacy class have the same characters, this may be...
Back
Top