Is a + b a Factor of a²(b + c) + b²(c + a) + c²(a + b) + 2abc?

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The discussion revolves around proving that a + b is a factor of the polynomial a²(b + c) + b²(c + a) + c²(a + b) + 2abc. Participants suggest rearranging the polynomial to factor it correctly and emphasize that a + b will be a factor if substituting a = -b results in the polynomial equaling zero. One user successfully factors the expression into (a + b)(c² + ab + ac + bc), indicating that the other factors can be derived from this. The conversation highlights confusion around the concept of proving factors in polynomials, with some participants seeking clarity on the proof process. Overall, the community aims to assist in understanding polynomial factorization and proof techniques.
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I tried, doubt I'm even close to correct. Show me where I went wrong or just guide me with the problem please.

Homework Statement


1.) Prove that a + b is a factor of a²(b + c) + b²(c + a) + c²(a + b) + 2abc and write down the other two factors.

2. The attempt at a solution

a^2(b - a) + b^2(-a + a) + (-a)^2(a + b) + 2ab(-a) = 0
a^2b - a^3 - b^2a + b^2a + a^2 + ab - 2ab = 0
a^2b - a^3 + a^2 - ab = 0a^2(-c + c) + (-c)^2(c +a) + c^2(a - c) + 2a(-c) = 0
-a^2c + a^2c + c^2 + ac + c^2a - c^3 - 2ac = 0
c^2 + c^2a - c^3 - ac = 0

(-b)^2(b + c) + b^2(c - b) + c^2(-b + b) + 2(-b)bc = 0
b^2 + bc + b^2c - b^3 - c^2b + c^2b - 2bc = 0
b^2 + b^2c - b^3 - bc = 0
 
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You're not given that a^2(b + c) + b^2(c + a) + c^2(a + b) + 2abc is equal to zero. All you're supposed to be doing is to rearrange what you have to put it into a factored form.

Having said that, how does the following expression relate to the expression above?
a^2(b - a) + b^2(-a + a) + (-a)^2(a + b) + 2ab(-a)

Also, are you sure that you have typed the problem exactly as it was given to you? I was able to factor the given expression into (b + c) times another factor, but I haven't been able to write it yet as (a + b) times another factor.
 
No, a+ b is a factor. Think of this as a polynomial in a with b and c constants. a+ b= a-(-b) will be a factor if and only if setting a= -b makes the polynomial equal to 0. And, of course, you can find the other factor by dividing by a+b.
 
Hi!:smile:
Solution to this is quite simple..
1st open the brackets
:. you have
a2b+ab 2+b2c+c2b+a2c+c2a+2abc
=ab(a+b) +b2c+a2c+c2b+c2a+2abc=ab(a+b)+c 2(a+b)+b2c+a2c+2abc
= (ab+c 2)(a+b)+c(b 2+a 2+2ab)
=(ab+c 2)(a+b)+c(a+b)2
=(a+b)(c2+ab+ac+bc)
That's what I think.
(there could be some mistakes while typing in powers because I kinda get confused while typing them)
I hope this helps!:smile:
 
Yes, I typed the question exactly as it was given.
I'm not sure how to 'prove'. The teacher keeps giving these proofs and I get baffled by them.
 
HallsofIvy said:
a+ b= a-(-b) will be a factor if and only if setting a= -b makes the polynomial equal to 0.

a + b = 0, and so
a = -b or b = -a
 
Last edited:
Hey what's the big deal then .
You "PROVE" it by giving the definition of factor and as it suits this condition :. You can say it is a factor of it.
See if it helps(?)
 
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