Is Charge Conserved in Proton-Helium Collision Reactions?

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SUMMARY

The discussion centers on the conservation of charge in proton-helium collision reactions, specifically regarding the minimum lab kinetic energy required to produce an anti-proton. It is established that charge is conserved, and the correct final state of the reaction includes one proton, one anti-proton, and one helium nucleus. The conservation of baryon number is also emphasized, indicating that producing a proton-anti-proton pair is necessary. The energy required for this particle-antiparticle production is quantified as 2mc², where m represents the mass of one of the particles.

PREREQUISITES
  • Understanding of particle physics concepts, specifically proton and anti-proton interactions.
  • Familiarity with conservation laws, including charge and baryon number conservation.
  • Knowledge of kinetic energy calculations in particle collisions.
  • Basic principles of quantum mechanics related to particle creation.
NEXT STEPS
  • Research the energy thresholds for particle-antiparticle production in high-energy physics.
  • Study the implications of baryon number conservation in nuclear reactions.
  • Explore the role of electromagnetic interactions in particle collisions.
  • Learn about laboratory techniques for measuring kinetic energy in particle accelerators.
USEFUL FOR

This discussion is beneficial for physics students, particle physicists, and researchers interested in nuclear reactions and conservation laws in high-energy collisions.

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Homework Statement


The problem is:
A proton collides with a Helium nucleus. What is the minimum lab kinetic energy needed to produce an anti-proton?


Homework Equations





The Attempt at a Solution


I suppose that helium nucleus is at rest in the lab frame.
I'm wondering about the final particles of this reaction.
Originally, I guess the result is a proton, an anti-proton and the helium nucleus, but in this way, the charge is not conserved. So I guess the final particles are two protons , an anti-proton and helium nucleus, but my friend told me that the standard answer in the text is that the final state is with one proton, one anti-proton and one helium nucleus.
So, the charge can be not conserved in a reaction?
(This means that the interaction is not electromagnetic?)

Thanks for all ideas.
 
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Charge is certainly conserved and your friend is wrong. Your guess is correct. Notice you also need to conserve baryon number. Producing a proton, anti-proton pair is really your only choice.
 
Yeah, the energy for particle-antiparticle production is always 2mc^2, where m is the mass of one of the particles.
 

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