Is Energy Lost When a Liquid Vaporizes and Gained When a Gas Condenses?

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When a liquid vaporizes, energy is absorbed from the system, calculated by q = m x lv, but according to the first law of thermodynamics, this energy is not lost; it is transformed. During vaporization, the internal energy of the gas increases as molecular bonds break, leading to an increase in potential energy. Conversely, when a gas condenses into a liquid, heat is released, indicating that energy is lost from the gas as it does work on the surroundings and its volume decreases. The process of condensation results in a decrease in molecular potential energy. Overall, energy is conserved throughout these phase changes, aligning with thermodynamic principles.
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when a liquid vaporises to a gas,
q = m x lv

this energy is lost?

also, what does this mean for when a gas turns to a liquid is q added to the system, or lost (added i presume??)
cheers
 
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jackcie said:
when a liquid vaporises to a gas,
q = m x lv

this energy is lost?
The first law of thermodynamics says that it cannot be lost: \Delta Q = \Delta U + W. The heat flow of vaporization has to be equal to the work done by the gas plus the change in internal energy of the gas.

When water, for example, vaporizes, it expands doing work on the surrounding atmosphere. Also internal energy increases. Although the temperature of the water does not change in vaporization, the bonds between water molecules are broken in the vaporization, thereby increasing the potential energy of the gas.
also, what does this mean for when a gas turns to a liquid is q added to the system, or lost (added i presume??)
cheers
It depends on the gas. When water vapor condenses heat flows out of the gas with the loss of molecular potential energy and work is done on the gas by the surroundings as the volume decreases.

AM
 
jackcie said:
when a liquid vaporises to a gas,
q = m x lv

this energy is lost?

also, what does this mean for when a gas turns to a liquid is q added to the system, or lost (added i presume??)
cheers

(quoting the OP)
 
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