I Is Euler's Identity Applicable to Transforming f(x)=constant*e^(-x^2)?

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Euler's identity cannot be directly applied to transform the function f(x) = constant * e^(-x^2) into the form f(x) = constant * e^(ix)^2. The expression e^(-x^2) can be rewritten as e^(i(ix^2)), but this results in imaginary arguments for sine and cosine, which complicates the analysis. While there is an equivalent formula involving hyperbolic functions (sinh and cosh), it may not provide the desired simplification. The discussion highlights the challenges of using Euler's identity in this context. Ultimately, the transformation does not yield a straightforward application of the identity.
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I have a homework question and I am wondering if you can use Eulers identity in this case.

If the equation is f(x)=constant*e^(-x^2) can this be rewritten as f(x)=consant*e^(ix)^2
and then, can you use the identity when it is in this form?

Edit: Can it be put in the form cosx+isinx

I am not well acquainted with Eulers Identity so bear with me
 
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zpatenaude37 said:
I have a homework question and I am wondering if you can use Eulers identity in this case.

If the equation is f(x)=constant*e^(-x^2) can this be rewritten as f(x)=consant*e^(ix)^2
and then, can you use the identity when it is in this form?

I am not well acquainted with Eulers Identity so bear with me
What do you propose to do with $${e^{(ix)}}^2$$
 
sorry edited for clarity
 
zpatenaude37 said:
sorry edited for clarity
Sadly ##exp((ix)^2) \ne (exp(ix))^2## if that's what you intended.
 
You can use ##\exp(-x^2) = \exp(i (ix^2))## and use the Euler formula for that expression, but that gives imaginary arguments for the sine and cosine, which does not look helpful.
 
zpatenaude37 said:
I have a homework question and I am wondering if you can use Eulers identity in this case.

If the equation is f(x)=constant*e^(-x^2) can this be rewritten as f(x)=consant*e^(ix)^2
and then, can you use the identity when it is in this form?

Edit: Can it be put in the form cosx+isinx

I am not well acquainted with Eulers Identity so bear with me
There is an equivalent formula involving sinh and cosh, but I doubt if it would help you.
 
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