MHB Is $f$ a function or a functional?

OhMyMarkov
Messages
81
Reaction score
0
Hello everyone!

I'm a bit confused about referring to a mapping as function or functional, for example: $f(x_1, x_2, x_3) = x_1+2x_2 ^2+3x_3 ^3$. $f$ takes vector $\textbf{x}=[x_1 \; x_2 \; x_3]$ and maps it to a scalar. Now, is $f$ a function or a functional?

Thanks!
 
Physics news on Phys.org
It's both, in this case. A functional is a function that maps a vector from a vector space into the field over which the vector space is defined. So all functionals are functions, but not all functions are functionals. Does that help?
 
Ackbach said:
It's both, in this case. A functional is a function that maps a vector from a vector space into the field over which the vector space is defined. So all functionals are functions, but not all functions are functionals. Does that help?

Not really sure unless, say, a counter example would be a continuous transform such as the continuous Fourier transform?
 
OhMyMarkov said:
Not really sure unless, say, a counter example would be a continuous transform such as the continuous Fourier transform?

Sure. The result of a Fourier transform is another function (or vector, depending on your vector space). Another counterexample is any matrix transformation, such as a rotation.
 
##\textbf{Exercise 10}:## I came across the following solution online: Questions: 1. When the author states in "that ring (not sure if he is referring to ##R## or ##R/\mathfrak{p}##, but I am guessing the later) ##x_n x_{n+1}=0## for all odd $n$ and ##x_{n+1}## is invertible, so that ##x_n=0##" 2. How does ##x_nx_{n+1}=0## implies that ##x_{n+1}## is invertible and ##x_n=0##. I mean if the quotient ring ##R/\mathfrak{p}## is an integral domain, and ##x_{n+1}## is invertible then...
The following are taken from the two sources, 1) from this online page and the book An Introduction to Module Theory by: Ibrahim Assem, Flavio U. Coelho. In the Abelian Categories chapter in the module theory text on page 157, right after presenting IV.2.21 Definition, the authors states "Image and coimage may or may not exist, but if they do, then they are unique up to isomorphism (because so are kernels and cokernels). Also in the reference url page above, the authors present two...
When decomposing a representation ##\rho## of a finite group ##G## into irreducible representations, we can find the number of times the representation contains a particular irrep ##\rho_0## through the character inner product $$ \langle \chi, \chi_0\rangle = \frac{1}{|G|} \sum_{g\in G} \chi(g) \chi_0(g)^*$$ where ##\chi## and ##\chi_0## are the characters of ##\rho## and ##\rho_0##, respectively. Since all group elements in the same conjugacy class have the same characters, this may be...

Similar threads

Back
Top