Is F = Δp/Δt Equal to F = ma in This Algebra Question?

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The discussion centers on the relationship between the equations F = Δp/Δt and F = ma. It confirms that Δt can be interpreted as dt in the context of calculus, where Δ represents a finite difference and d represents an infinitesimal change. The equations are shown to be equivalent by substituting momentum (p = mΔv) and acceleration (a = Δv/Δt). There is a clarification that the original notation used was correct, and the confusion arose from a typographical error. The conclusion affirms the validity of the relationship between the two formulas.
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Hi all. Am I correct in that dt = Δt?
Thankyou!

Homework Statement


Show that F = \frac{Δp}{Δt} is equal to F = ma

Homework Equations


a = \frac{Δv}{Δt}
p = mΔv

The Attempt at a Solution


F = \frac{Δp}{Δt}
F = \frac{mΔv}{Δt}
F = ma
 
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JoshuaOB said:
Hi all. Am I correct in that dt = Δt?
Thankyou!

Homework Statement


Show that F = \frac{Δp}{Δt} is equal to F = ma


Homework Equations


a = \frac{Δv}{Δt}
p = mΔv


The Attempt at a Solution


F = \frac{Δp}{Δt}
F = \frac{mΔv}{Δt}
F = ma

Δ usually means a finite difference. You can replace Δ with d in the limit where the difference goes to 0. In this case, I think they probably should have used d to begin with. So yes, I think that should be ok.
 
My apologies, they did use d to begin with. I typed it incorrectly.
 
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