Is <f,g> an Inner Product on C[a,b]?

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Homework Statement


show that if we define the following operation:
let f=f(x) and g=g(x) be two functions in C[a,b] and define <f,g>=int(a to b) f(x)g(x)dx
show that the conditions of therom are satisified with this operation. Use h=h(x) to help with part b
this shows that this operation is an inner product
therom


Homework Equations


a. u dot v = v dot u
b. (u+v) dot w = u dot w + v dot w
c. (cu) dot v = c(u dot v) = u dot (cv)
d. u dot u >= 0, and u dot u = 0 if and only if u = 0


The Attempt at a Solution


I really have no idea where to begin here...
 
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I assume you are trying to prove that your structure is an inner product. For reference, <f,g> is just a generalized way of writing a dot product (as a dot product is just one specific inner product). So what you need to prove is:

a. <f,g> = <g,f>
b. <f+g,h> = <f,h> + <g,h>
c. <cf,g> = c<f,g> = <f,cg> where c is a scalar, not a function

and so on. Plug and chug, almost.
 
Last edited:
Hi sorry. I'm still pretty confused. Is there anyway you could elaborate?
 
Shaunzio said:

Homework Statement


show that if we define the following operation:
let f=f(x) and g=g(x) be two functions in C[a,b] and define <f,g>=int(a to b) f(x)g(x)dx
show that the conditions of therom are satisified with this operation. Use h=h(x) to help with part b
this shows that this operation is an inner product
therom
It's rather confusing for us to use "<f, g>" above and "u dot v" below!


Homework Equations


a. u dot v = v dot u
So you want to prove that
&lt;f, g&gt;= \int_a^b f(x)g(x)dx= \int_a^b g(x)f(x)dx= &lt;g, f&gt;

b. (u+v) dot w = u dot w + v dot w
So you want to prove that
&lt;f+ g, h&gt;= \int_a^b (f(x)+ g(x))h(x) dx= \int_a^b f(x)h(x) dx+ \int_a^b g(x)h(x) dx= &lt;f, h&gt;+ &lt;g, h&gt;

c. (cu) dot v = c(u dot v) = u dot (cv)
So you want to prove that
&lt;cf, g&gt;= \int_a^b (cf(x))g(x)dx= c\int_a^b f(x)g(x)dx= \int_a^b f(x)(cg(x))dx

d. u dot u >= 0, and u dot u = 0 if and only if u = 0
So you want to prove that
&lt;f, f&gt;= \int_a^b f^2(x)dx\ge 0
and
&lt;f, f&gt;= \int_a^b f^2(x)dx= 0
if and only if f(x)= 0 for all x between a and b.


The Attempt at a Solution


I really have no idea where to begin here...
Did you not consider writing out what you want to prove in terms of the given definition?
 
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