Noorac
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f(x)
=\frac{arctan x}{x} for x different from 0
= 1 for x equal to 0
F(x) is a definite integral from 0 to x, but I couldn't find the code for it, so just assume it is from 0 to x in the equation below.
F(X) = \int f(t) dt
Now, the task is to prove that F(-x) = -F(x).
This means we need to prove:
\int f(t) dt : definite from 0 to -x
=
-\int f(t) dt : definite from 0 to x
_____________________________________
We have tried some basic manipulation of integrals, but came nowhere.
If anyone can give a hint of how to prove this, or tell us if we have understood the problem wrong, we would be most grateful.
Thanks.
=\frac{arctan x}{x} for x different from 0
= 1 for x equal to 0
F(x) is a definite integral from 0 to x, but I couldn't find the code for it, so just assume it is from 0 to x in the equation below.
F(X) = \int f(t) dt
Now, the task is to prove that F(-x) = -F(x).
This means we need to prove:
\int f(t) dt : definite from 0 to -x
=
-\int f(t) dt : definite from 0 to x
_____________________________________
We have tried some basic manipulation of integrals, but came nowhere.
If anyone can give a hint of how to prove this, or tell us if we have understood the problem wrong, we would be most grateful.
Thanks.