Is Integration by Parts the Key to Solving Complex Equations?

Ein Krieger
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Hey guys,

Need you push to proceed further with integration by parts:

∫e3x*3*x2*ydx=y∫e3x*3*x2dx

setting u=3*x2-------du=6*x dx
dv= e3*xdx--- v= 1/3* e3*x

∫ e3*x*3*x2*ydx=y*(3*x2* 1/3* e3*x-∫6*x*1/3* e3*xdx)
=y*(3*x2* 1/3* e3*x-6/3*∫x*e3*xdx)
Solving further about x*e3*x
u=x---du=dx
dv=e3*xdx---v=1/3*e3*x
∫ e3*x*3*x2*ydx=y*(3*x2* 1/3* e3*x-6/3*(x*1/3*e3*x-∫1/3e3*x)
 
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How can we go further with solution as exp(3*x) repeats all the time?
 


You've done all the hard work. ∫e3xdx is easy, using a simple substitution.
 


If you have \int x^n f(x)dx, where "f" is easy to integrate any number of times (and the "nth" integral of e^{3x} is (1/3^n)e^{3x}), just continue taking u= x^n, dv= f(x)dx. Everytime du will have x to a lower power until, eventually, it is just x^0= 1.
 
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